Question 32

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Jambmaths question: 

If $\frac{\pi }{2}\le \theta \le 2\pi $, Find the maximum value of $f(\theta )=\frac{4}{6+2\cos \theta }$

Option A: 

4

Option B: 

1

Option C: 

$\tfrac{2}{3}$

Option D: 

$\frac{1}{2}$

Jamb Maths Solution: 

The maximum value of f(θ) will exist when 2cos θ is minimum. The minimum 2cos θ can be is zero, that is when θ is 90oThe maximum value is $\frac{4}{6+2\cos {{90}^{o}}}=\frac{4}{6+0}=\frac{2}{3}$

 

 

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