Question 32


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Jambmaths question: 

A box contains 5blue balls, 3 red balls and 2 white balls. Two balls were selected from the box with replacement. Find the probability of obtaining two blue or two red balls

Option A: 


Option B: 


Option C: 


Option D: 


Jamb Maths Solution: 

Total number of balls = 5 + 3 + 2 = 10Prob. Of 2 blue balls = $\tfrac{5}{10}\times \tfrac{5}{10}=\tfrac{25}{100}=\tfrac{1}{4}$Prob. Of 2 red balls = $\tfrac{3}{10}\times \tfrac{3}{10}=\tfrac{9}{100}$Prob. Of 2 blue or two red ball = $\tfrac{1}{4}+\tfrac{9}{100}=\tfrac{25+9}{100}=\tfrac{34}{100}=\tfrac{17}{50}$

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