Question 32

loading...

Prev/Next links

waecmaths question: 

If $\sqrt{72}+\sqrt{32}-3\sqrt{18}=x\sqrt{8}$ find the value of x

Option A: 

1

Option B: 

$\tfrac{3}{4}$

Option C: 

$\tfrac{1}{2}$

Option D: 

$\tfrac{1}{4}$

waecmaths solution: 

$\begin{align}  & \sqrt{72}+\sqrt{32}-3\sqrt{18}=x\sqrt{8} \\ & \sqrt{36\times 2}+\sqrt{16\times 2}-3\sqrt{9\times 2}=x\sqrt{4\times 2} \\ & 6\sqrt{2}+4\sqrt{2}-9\sqrt{2}=2x\sqrt{2} \\ & \sqrt{2}=2x\sqrt{2} \\ & x=\frac{1}{2} \\\end{align}$

maths year: 
maths topics: