Question 32

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Jambmaths question: 

The gradient of the straight line joining the point P(5, –7) and Q(–2, –3) is

Option A: 

$\tfrac{1}{2}$

Option B: 

$\tfrac{2}{5}$

Option C: 

$-\tfrac{4}{7}$

Option D: 

$-\tfrac{2}{3}$

Jamb Maths Solution: 

$\begin{align}  & \text{Gradient }=m \\ & m=\frac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}} \\ & ({{x}_{1}},{{y}_{1}})=(5,-7) \\ & ({{x}_{2}},{{y}_{2}})=(-2,-3) \\ & m=\frac{-3-(-7)}{-2-5}=\frac{-3+7}{-2-5} \\ & m=-\frac{4}{7} \\\end{align}$

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