Question 32

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waecmaths question: 

Simplify $\frac{\log \sqrt{8}}{\log 4-\log 2}$

Option A: 

$\frac{2}{3}$

Option B: 

$\tfrac{1}{2}\log 2$

Option C: 

$\tfrac{3}{2}$

Option D: 

$\log 2$

waecmaths solution: 

$\frac{\log \sqrt{8}}{\log 4-\log 2}=\frac{\log {{8}^{\tfrac{1}{2}}}}{\log {{2}^{2}}-\log 2}=\frac{\tfrac{1}{2}\log {{2}^{3}}}{2\log 2-\log 2}=\frac{\tfrac{3}{2}\log 2}{\log 2}=\frac{3}{2}$

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