Question 32

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Jambmaths question: 

Find the minimum value of the function $f(\theta )=\frac{2}{3-\cos \theta }\text{ for }0\le \theta \le 2\pi $

Option A: 

½

Option B: 

$\tfrac{2}{3}$

Option C: 

1

Option D: 

2

Jamb Maths Solution: 

The function$f(\theta )=\frac{2}{3-\cos \theta }$will have minimum value when 3 – cos θ has maximum value. This will occur when θ = 0o.

$f(0)=\frac{2}{3-\cos 0}=\frac{2}{3-1}=\frac{2}{2}=1$

The maximum value of $f(\theta )$is 1  (Option C)

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