Question 33

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Jambmaths question: 

In a triangle PQR, q =8cm,r = 6cm and$\cos P=\tfrac{1}{12}$. Calculate the value of p

Option A: 

9cm

Option B: 

$\sqrt{92}cm$

Option C: 

10cm

Option D: 

$\sqrt{108}cm$

Jamb Maths Solution: 

$\begin{align}  & \text{using cosine rule } \\ & {{p}^{2}}={{r}^{2}}+{{q}^{2}}-2rq\cos P \\ & {{p}^{2}}={{6}^{2}}+{{8}^{2}}-2(6)(8)(\tfrac{1}{12}) \\ & {{p}^{2}}=100-8 \\ & p=\sqrt{92}cm \\\end{align}$

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