Question 34

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waecmaths question: 

Express $3-\left[ \frac{x-y}{y} \right]$ as a single fraction

Option A: 

$\frac{3xy}{y}$

Option B: 

$\frac{x-4y}{y}$

Option C: 

$\frac{4y+x}{y}$

Option D: 

$\frac{4y-x}{y}$

waecmaths solution: 

$\begin{align}  & 3-\left[ \frac{x-y}{y} \right]=\frac{3y-(x-y)}{y} \\ & =\frac{3y-x+y}{y} \\ & =\frac{4y-x}{y} \end{align}$

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