Question 34

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Jambmaths question: 

Find the equation of the line through the points  (–2, 1) and (–½, 4)

Option A: 

y = 2x – 3

Option B: 

y = 2x + 5

Option C: 

y =3x – 2

Option D: 

y = 2x +1

Jamb Maths Solution: 

$\begin{align}  & \text{Using two point form equation} \\ & \frac{y-{{y}_{1}}}{x-{{x}_{1}}}=\frac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}} \\ & ({{x}_{1}},{{y}_{1}})=(-2,1),\text{ }({{x}_{2}},{{y}_{2}})=(-\tfrac{1}{2},4) \\ & \frac{y-1}{x-(-2)}=\frac{4-1}{-\tfrac{1}{2}+2} \\ & \frac{y-1}{x+2}=\frac{3}{\tfrac{3}{2}} \\ & \frac{y-1}{x+2}=2 \\ & y-1=2(x+2) \\ & y=2x+5 \\\end{align}$

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