Question 34

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waecmaths question: 

Find the value of a if ${{\log }_{10}}a+{{\log }_{10}}{{a}^{2}}=0.9030$

Option A: 

4.0

Option B: 

2.0

Option C: 

1.6

Option D: 

0.0

waecmaths solution: 

$\begin{align}  & {{\log }_{10}}a+{{\log }_{10}}{{a}^{2}}=0.9030 \\ & {{\log }_{10}}{{a}^{3}}=0.9030 \\ & 3{{\log }_{10}}a=0.9030 \\ & {{\log }_{10}}a=0.3010 \\ & a={{10}^{0.3010}}=2 \\\end{align}$

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