Question 35

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Jambmaths question: 

What is the probability that an integer x $(1\le x\le 20)$chosen at random is divisible by both 2 and 3

Option A: 

$\tfrac{3}{20}$

Option B: 

$\tfrac{7}{10}$

Option C: 

$\tfrac{1}{20}$

Option D: 

$\tfrac{1}{3}$

Jamb Maths Solution: 

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18.19,20

Total possible outcome =20

Number divisible by both 2 and 3 are 6,12, 18

Number of expected outcome = 3

$Probability=\frac{number of expected outcome}{number of total possible outcome}$

$Probability(\text{ divisible by 2 and 3)}=\frac{3}{20}$

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