Question 35


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Jambmaths question: 

What is the probability that an integer x $(1\le x\le 20)$chosen at random is divisible by both 2 and 3

Option A: 


Option B: 


Option C: 


Option D: 


Jamb Maths Solution: 


Total possible outcome =20

Number divisible by both 2 and 3 are 6,12, 18

Number of expected outcome = 3

$Probability=\frac{number of expected outcome}{number of total possible outcome}$

$Probability(\text{ divisible by 2 and 3)}=\frac{3}{20}$

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