Question 35

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Jambmaths question: 

If $T=2\pi \sqrt{\frac{l}{g}}$make g the subject of formula

Option A: 

$\frac{4\pi {{l}^{2}}}{T}$

Option B: 

$\frac{4{{\pi }^{2}}l}{{{T}^{2}}}$

Option C: 

$\frac{4{{\pi }^{2}}{{l}^{2}}}{{{T}^{2}}}$

Option D: 

$\frac{2\pi \sqrt{l}}{T}$

Jamb Maths Solution: 

$\begin{align}  & T=2\pi \sqrt{\frac{l}{g}} \\ & \frac{T}{2\pi }=\sqrt{\frac{l}{g}}\text{       }\!\!\{\!\!\text{ Divide both sides by }2\pi \} \\ & \frac{{{T}^{2}}}{4{{\pi }^{2}}}=\frac{l}{g}\text{        }\!\!\{\!\!\text{ Square both sides }\!\!\}\!\!\text{ } \\ & \frac{g{{T}^{2}}}{4{{\pi }^{2}}}=l\text{        }\!\!\{\!\!\text{ Multiply both sides by }g\} \\ & g=\frac{4{{\pi }^{2}}l}{{{T}^{2}}}\text{      }\!\!\{\!\!\text{ Multiply both sides by }\tfrac{4{{\pi }^{2}}}{{{T}^{2}}}\} \\\end{align}$

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