Question 35

loading...

Prev/Next links

Jambmaths question: 

A man 40m from the foot of tower observes the angle of elevation of the tower to be 30o. Determine the height of the tower

Option A: 

40$\sqrt{3}$

Option B: 

$\frac{40\sqrt{3}}{3}$

Option C: 

40

Option D: 

20

Jamb Maths Solution: 

$\begin{align}  & \tan {{30}^{\text{o}}}=\frac{h}{40} \\ & h=40\tan {{30}^{\text{o}}} \\ & h=\frac{40}{\sqrt{3}}=\frac{40\times \sqrt{3}}{\sqrt{3}\times \sqrt{3}}=\frac{40\sqrt{3}}{3} \\\end{align}$

Jamb Maths Topic: 
Year of Exam: