Question 35

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Jambmaths question: 

A man walks 100m due west from a point X to Y, he then walks 100m due North to a point Z. Find the bearing of X from Z

Option A: 

225o

Option B: 

045o

Option C: 

135o

Option D: 

195o

Jamb Maths Solution: 

$\tan \beta =\frac{XY}{YZ}=\frac{100}{100}=1$

$\beta ={{\tan }^{-1}}1={{45}^{\circ }}$

The bearing of X from Z is 270o­­­­ - 45o = 225o

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