Question 35

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Jambmaths question: 

Solve the inequality $(x+4)(x+1)\le 0$

Option A: 

$4\le x\le -1$

Option B: 

$1\le x\le 4$

Option C: 

$-4\le x\le -1$

Option D: 

$-1\le x\le 4$

Jamb Maths Solution: 

We use the inequality table to determine  the range

 

x$\le $-4

-4$\le $ x$\le $ -1

x$\ge $ -1

(x+4)

-ve

+ve

+ve

(x+1)

-ve

-ve

+ve

(x+4)(x+1)

+ve

-ve

+ve

The range is $-4\le x\le -1$

$(x+4)(x+1)\le 0$

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