Question 36

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waecmaths question: 

If $\frac{2}{x-3}-\frac{3}{x-2}$is equal to $\frac{P}{(x-3)(x-2)}$ find P

Option A: 

x – 5

Option B: 

–(x +3)

Option C: 

(5x – 13)

Option D: 

5 – x

waecmaths solution: 

$\begin{align}  & \frac{2}{x-3}-\frac{3}{x-2}=\frac{2(x-2)-3(x-3)}{(x-3)(x-2)} \\ & \frac{2}{x-3}-\frac{3}{x-2}=\frac{2x-4-3x+9}{(x-3)(x-2)} \\ & \frac{2}{x-3}-\frac{3}{x-2}=\frac{5-x}{(x-3)(x-2)} \\\end{align}$

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