Question 37

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Jambmaths question: 

If $y={{(1+x)}^{2}},$find $\frac{dy}{dx}$

Option A: 

2x+2

Option B: 

1+2x

Option C: 

2x -1

Option D: 

x -1

Jamb Maths Solution: 

$\begin{align}  & y={{(1+x)}^{2}} \\ & \text{Using the chain or composite rule} \\ & \text{Let }u=1+x \\ & y={{u}^{2}} \\ & \frac{dy}{du}=2u \\ & \frac{du}{dx}=1 \\ & \frac{dy}{dx}=\frac{dy}{du}\times \frac{du}{dx}=2u\times 1 \\ & \frac{dy}{dx}=2u=2(1+x) \\ & \frac{dy}{dx}=2+2x \\\end{align}$

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