Question 37

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Jambmaths question: 

Find the derivative of $\frac{\sin \theta }{\cos \theta }$

Option A: 

$\text{cosec}\theta \sec \theta$

Option B: 

$\text{cosec}{{\text{c}}^{2}}\theta$ 

Option C: 

$\tan \theta \text{cosec}\theta$

Option D: 

${{\sec }^{2}}\theta$

Jamb Maths Solution: 

$\begin{align}  & \frac{\sin \theta }{\cos \theta }=\tan \theta  \\ & \frac{d}{dx}\left( \frac{\sin \theta }{\cos \theta } \right)=\frac{d}{dx}(\tan \theta )={{\sec }^{2}}\theta  \\\end{align}$

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