Question 38

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waecmaths question: 

A man’s eye level is 1.7m above the horizontal ground and 13m from a vertical pole. If the pole is 8.3m high, calculate, correct to the nearest degree, the angle of elevation of the top of the pole from his eyes

Option A: 

33o

Option B: 

32o

Option C: 

27o

Option D: 

26o

waecmaths solution: 

$\begin{align}  & \tan \theta =\frac{6.6}{13} \\ & \theta ={{\tan }^{-1}}(\tfrac{6.6}{13})=26.91 \\ & \theta \approx {{27}^{\circ }} \\\end{align}$

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