Question 38

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Jambmaths question: 

Factorize completely $ac-2bc-{{a}^{2}}+4{{b}^{2}}$

Option A: 

$(a-2b)(c-a-2b)$

Option B: 

$(a-2b)(c+a+2b)$

Option C: 

$(a-2b)(c-a+2b)$

Option D: 

$(a-2b)((c+a-2b)$

Jamb Maths Solution: 

$\begin{align}  & ac-2bc-{{a}^{2}}+4{{b}^{2}}=c(a-2b)(-a+2b)(a+2b) \\ & =c(a-2b)-1(a-2b)(a+2b) \\ & =(a-2b)\left[ c-(a+2b) \right] \\ & =(a-2b)(c-a-2b) \end{align}$

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