Question 38

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Jambmaths question: 

If $\cot \theta =\tfrac{8}{15},\text{ where }\theta \text{ is acute, find }\sin \theta $

Jamb Maths Solution: 

$\begin{align}  & \cot \theta =\frac{adj}{opp} \\ & A{{C}^{2}}={{15}^{2}}+{{8}^{2}} \\ & AC=\sqrt{225+64}=\sqrt{289}=17 \\ & \therefore \sin \theta =\frac{opp}{hyp}=\frac{15}{17} \\\end{align}$

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