Question 38

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Jambmaths question: 

If $y=4{{x}^{3}}-2{{x}^{2}}+x$, find $\tfrac{dy}{dx}$

Option A: 

$8{{x}^{2}}-4x+1$

Option B: 

$12{{x}^{2}}-2x+1$

Option C: 

$12{{x}^{2}}-2x+1$

Option D: 

$8{{x}^{2}}-2x+1$

Jamb Maths Solution: 

$\begin{align}  & y=4{{x}^{3}}-2{{x}^{2}}+x \\ & \frac{dy}{dx}=12{{x}^{2}}-4x+1 \\\end{align}$

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