Question 39

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waecmaths question: 

Find the smaller value of x that satisfies the equation ${{x}^{2}}+7x+10=0$

Option A: 

–5

Option B: 

–2

Option C: 

2

Option D: 

5

waecmaths solution: 

$\begin{align}  & {{x}^{2}}+7x+10=0 \\ & (x+5)(x+2)=0 \\ & x=-5\text{ or }x=-2 \\\end{align}$The least value is –5 

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