Question 39

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Jambmaths question: 

$\text{Evaluate }\int_{0}^{\tfrac{\pi }{4}}{\sin xdx}$

Option A: 

2

Option B: 

1

Option C: 

-1

Option D: 

-2

Jamb Maths Solution: 

$\begin{align}  & \int_{0}^{\frac{\pi }{2}}{\sin xdx}=\left[ -\cos x \right]_{0}^{\tfrac{\pi }{2}}=-\cos \tfrac{\pi }{2}-(-\cos 0) \\ & \text{where }\tfrac{\pi }{2}radian={{90}^{\circ }} \\ & \int_{0}^{\frac{\pi }{2}}{\sin xdx}=-0-(-1)=1 \\\end{align}$

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