Question 39

loading...

Prev/Next links

waecmaths question: 

If $p=\frac{1}{2}$ and $\frac{1}{p-1}=\frac{2}{p+x}$ , find the value of x

Option A: 

–2 ½ 

Option B: 

–1½

Option C: 

Option D: 

waecmaths solution: 

$\begin{align}  & \frac{1}{p-1}=\frac{2}{p+x} \\ & \frac{1}{\tfrac{1}{2}-1}=\frac{2}{\tfrac{1}{2}+x} \\ & \frac{1}{-\tfrac{1}{2}}=\frac{2}{\tfrac{1+2x}{2}} \\ & -2=\frac{4}{1+2x} \\ & -2(1+2x)=4 \\ & -2-4x=4 \\ & -4x=6 \\ & x=-\frac{6}{4}=-\frac{3}{2}=-1\tfrac{1}{2} \\\end{align}$

maths year: 
maths topics: