Question 4

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Jambmaths question: 

$\begin{align}  & \text{Evaluate }\frac{1.25\times 0.025}{0.05},\text{ correct to 1 decimal place} \\ & \text{(A)  0}\text{.6  (B) 6}\text{.2  (C) 6}\text{.3  (D)  }0.5 \\\end{align}$

Jamb Maths Solution: 

$\begin{align}  & \frac{1.25\times 0.025}{0.05}=\frac{125\times {{10}^{-2}}\times 25\times {{10}^{-3}}}{5\times {{10}^{-2}}} \\ & \frac{1.25\times 0.025}{0.05}=\frac{125\times 25}{5}\times {{10}^{-2-3+2}}=625\times {{10}^{-3}}=0.625 \\ & \frac{1.25\times 0.025}{0.05}\approx 0.6\text{ to 1 decimal place} \\\end{align}$

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