Question 4

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waecmaths question: 

Simplify $\sqrt{50}+\frac{10}{\sqrt{2}}$

Option A: 

10

Option B: 

$10\sqrt{2}$

Option C: 

20 

Option D: 

$20\sqrt{2}$

waecmaths solution: 

$\begin{align}  & \sqrt{50}+\frac{10}{\sqrt{2}}=\frac{\sqrt{100}+10}{\sqrt{2}}=\frac{10+10}{\sqrt{2}} \\ & =\frac{20}{\sqrt{2}}=\frac{20}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}=\frac{20\sqrt{2}}{2}=10\sqrt{2} \\\end{align}$

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