Question 40


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Jambmaths question: 

The triangle PQR above is

Option A: 

an obtuse – angled triangle

Option B: 

a scalene triangle

Option C: 

isosceles triangle

Option D: 

an equilateral triangle.

Jamb Maths Solution: 

$\begin{align}  & P\overset{\wedge }{\mathop{R}}\,Q={{180}^{\text{o}}}-{{128}^{\text{o}}}={{52}^{\text{o}}}\text{    }\!\!\{\!\!\text{ sum of }\angle \text{s on a straight line }\!\!\}\!\!\text{ } \\ & Q\overset{\wedge }{\mathop{P}}\,R+P\overset{\wedge }{\mathop{Q}}\,R+P\overset{\wedge }{\mathop{R}}\,Q={{180}^{\text{o}}}\text{   }\!\!\{\!\!\text{ sum of }\angle \text{s in a }\vartriangle \text{ }\!\!\}\!\!\text{ } \\ & Q\overset{\wedge }{\mathop{P}}\,R+{{76}^{\text{o}}}+{{52}^{\text{o}}}={{180}^{\text{o}}} \\ & Q\overset{\wedge }{\mathop{P}}\,R={{52}^{\text{o}}} \\ & \text{Since two of angles are equal},\text{ the triangle is an isosceles triangle} \\\end{align}$

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