Question 41

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waecmaths question: 

Express $\frac{2}{x+3}-\frac{1}{x-2}$ as a simple fraction

Option A: 

$\frac{x-7}{{{x}^{2}}+x-6}$

Option B: 

$\frac{x-1}{{{x}^{2}}+x-6}$

Option C: 

$\frac{x-2}{{{x}^{2}}+x-6}$

Option D: 

$\frac{x+7}{{{x}^{2}}+x-6}$

waecmaths solution: 

$\frac{2}{x+3}-\frac{1}{x-2}=\frac{2(x-2)-(x+3)}{(x+3)(x-2)}=\frac{2x-4-x-3}{{{x}^{2}}+x-6}=\frac{x-7}{{{x}^{2}}+x-6}$

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