Question 42

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waecmaths question: 

Make w the subject of the relation $\frac{a+bc}{wd+f}=g$

Option A: 

$\frac{a+bc-fg}{dg}$

Option B: 

$\frac{a-bc+fb}{dg}$

Option C: 

$\frac{a+bc-f}{dg}$

Option D: 

$\frac{a+bc-dg}{fg}$

waecmaths solution: 

$\begin{align}  & \frac{a+bc}{wd+f}=g \\ & a+bc=g(wd+f) \\ & \frac{a+bc}{g}=wd+f \\ & \frac{a+bc}{g}-f=wd \\ & \frac{a+bc-fg}{g}=wd \\ & \frac{a+bc-fg}{dg}=w \\\end{align}$ 

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