Question 44

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waecmaths question: 

For what value of y is the expression $\frac{6y-1}{{{y}^{2}}-y-6}$ not defined?

Option A: 

$\tfrac{1}{6},\tfrac{1}{4}$

Option B: 

3, –2

Option C: 

–3, 2

Option D: 

0, 1

waecmaths solution: 

The expression $\frac{6y-1}{{{y}^{2}}-y-6}$will undefined when ${{y}^{2}}-y-6=0$$\begin{align}  & {{y}^{2}}-y-6=0 \\ & (y-3)(y+2)=0 \\ & y=3\text{ or }y=-2 \\\end{align}$

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