Question 45

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waecmaths question: 

Find the smallest value of k such that ${{2}^{2}}\times {{3}^{3}}\times 5\times k$ is a perfect square 

Option A: 

3

Option B: 

5

Option C: 

15

Option D: 

30

waecmaths solution: 

$\begin{align}  & {{2}^{2}}\times {{3}^{3}}\times 5\times k={{2}^{2}}\times {{3}^{2}}\times 3\times 5\times k={{2}^{2}}\times {{3}^{2}}\times 15\times k \\ & \text{For perfect square }k=15 \\ & {{2}^{2}}\times {{3}^{3}}\times 5\times k={{2}^{2}}\times {{3}^{2}}\times 15\times 15 \\\end{align}$

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