Question 46

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waecmaths question: 

If ${{27}^{x}}={{9}^{y}}$ find the value of $\tfrac{x}{y}$

Option A: 

$\tfrac{1}{3}$

Option B: 

$\tfrac{2}{5}$

Option C: 

$1\tfrac{1}{2}$

Option D: 

3

waecmaths solution: 

$\begin{align}  & {{27}^{x}}={{9}^{y}} \\ & {{3}^{3x}}={{3}^{2y}} \\ & \text{Equating the powers} \\ & 3x=2y \\ & \frac{x}{y}=\frac{2}{3}=1\frac{2}{3} \\\end{align}$

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