Question 48

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waecmaths question: 

Find the number of terms in the Arithmetic Progression (A.P) 2, –9, –20, …. –141

Option A: 

11

Option B: 

12

Option C: 

13

Option D: 

14

waecmaths solution: 

$\begin{align}  & a=2 \\ & d=-11 \\ & {{T}_{n}}=a+(n-1)d \\ & -141=2+(n-1)(-11) \\ & -141=13-11n \\ & 11n=154 \\ & n=14 \\\end{align}$

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