Question 49

loading...

Prev/Next links

Jambmaths question: 

In how many ways can a committee of 2 women and 3 men be chosen from 6men and 5 women?

Jamb Maths Solution: 

$\begin{align}  & ^{6}{{C}_{3}}{{\times }^{5}}{{C}_{2}} \\ & \frac{6!}{3!(6-3)!}\times \frac{5!}{2!(5-2)!}=20\times 10=200 \\\end{align}$

Jamb Maths Topic: 
Year of Exam: