Question 5

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waecmaths question: 

The nth term of a sequence is ${{T}_{n}}=5+{{(n-1)}^{2}}$. Evaluate ${{T}_{4}}-{{T}_{6}}$

Option A: 

30

Option B: 

16

Option C: 

–16 

Option D: 

–30

waecmaths solution: 

$\begin{align}  & {{T}_{n}}=5+{{(n-1)}^{2}} \\ & {{T}_{4}}=5+{{(4-1)}^{2}}=5+{{3}^{2}}=14 \\ & {{T}_{6}}=5+{{(6-1)}^{2}}=5+{{5}^{2}}=30 \\ & {{T}_{4}}-{{T}_{6}}=14-30=-16 \\\end{align}$

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