Question 5

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waecmaths question: 

Find the equation whose roots are 2 and $-3\tfrac{1}{2}$

Option A: 

$2{{x}^{2}}+3x+14$

Option B: 

$2{{x}^{2}}+5x+7=0$

Option C: 

$2{{x}^{2}}+5x-7=0$

Option D: 

$2{{x}^{2}}+3x-14=0$

waecmaths solution: 

$\begin{align}  & (x-2)(x+3\tfrac{1}{2})=0 \\ & (x-2)(x+\tfrac{7}{2})=0 \\ & {{x}^{2}}+\tfrac{7x}{2}-2x-7=0 \\ & {{x}^{2}}+\tfrac{3x}{2}-7=0 \\ & 2{{x}^{2}}+3x-14=0 \\\end{align}$

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