Question 50

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waecmaths question: 

Factorize completely $32{{x}^{2}}y-48{{x}^{3}}{{y}^{3}}$

Option A: 

$16{{x}^{2}}y(2-3x{{y}^{2}})$

Option B: 

$8xy(4x-6{{x}^{2}}{{y}^{2}})$

Option C: 

$8{{x}^{2}}y(4-6x{{y}^{2}})$

Option D: 

$16xy(2x-3{{x}^{2}}{{y}^{2}})$

waecmaths solution: 

$32{{x}^{2}}y-48{{x}^{3}}{{y}^{3}}=16{{x}^{2}}y(2-3x{{y}^{2}})$

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