Question 50

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Jambmaths question: 

If $\frac{{{4}^{x+3}}}{{{16}^{2x-3}}}=1$ find x

Option A: 

1

Option B: 

–1

Option C: 

–3

Option D: 

3

Jamb Maths Solution: 

$\begin{align}  & \frac{{{4}^{x+3}}}{{{16}^{2x-3}}}=1 \\ & {{4}^{x+3}}={{16}^{2x-3}} \\ & {{2}^{2(x+3)}}={{2}^{4(2x-3)}} \\ & \text{Equating the powers} \\ & 2(x+3)=4(2x-3) \\ & 2x+6=8x-12 \\ & 6x=18 \\ & x=3 \\\end{align}$

Jamb Maths Topic: 
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