waecmaths question:
If $\sqrt{50}-k\sqrt{8}=\frac{2}{\sqrt{2}}$ find k
Option A:
–2
Option B:
–1
Option C:
1
Option D:
2
waecmaths solution:
$\begin{align} & \sqrt{50}-k\sqrt{8}=\frac{2}{\sqrt{2}} \\ & \sqrt{50}-\frac{2}{\sqrt{2}}=k\sqrt{8} \\ & \sqrt{100}-2=k\sqrt{16} \\ & 10-2=4k \\ & 8=4k \\ & k=2 \end{align}$
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