Question 6

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waecmaths question: 

If $\sqrt{50}-k\sqrt{8}=\frac{2}{\sqrt{2}}$ find k

Option A: 

–2

Option B: 

–1

Option C: 

1

Option D: 

2

waecmaths solution: 

$\begin{align}  & \sqrt{50}-k\sqrt{8}=\frac{2}{\sqrt{2}} \\ & \sqrt{50}-\frac{2}{\sqrt{2}}=k\sqrt{8} \\ & \sqrt{100}-2=k\sqrt{16} \\ & 10-2=4k \\ & 8=4k \\ & k=2 \end{align}$

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