Question 6

loading...

Prev/Next links

Jambmaths question: 

Simplify ${{\left( \frac{16}{81} \right)}^{\tfrac{1}{4}}}\div {{\left( \frac{9}{16} \right)}^{-\tfrac{1}{2}}}$

Option A: 

$\tfrac{8}{9}$

Option B: 

$\tfrac{1}{3}$

Option C: 

$\tfrac{1}{2}$

Option D: 

$\tfrac{2}{3}$

Jamb Maths Solution: 

$\begin{align}  & {{\left( \frac{16}{81} \right)}^{\tfrac{1}{4}}}\div {{\left( \frac{9}{16} \right)}^{-\tfrac{1}{2}}}={{\left( \frac{16}{81} \right)}^{\tfrac{1}{4}}}\times {{\left( \frac{16}{9} \right)}^{-\tfrac{1}{2}}}={{\left( \frac{{{2}^{4}}}{{{3}^{4}}} \right)}^{\tfrac{1}{4}}}\times {{\left( \frac{{{4}^{2}}}{{{3}^{2}}} \right)}^{-\frac{1}{2}}} \\ & {{\left( \frac{16}{81} \right)}^{\tfrac{1}{4}}}\div {{\left( \frac{9}{16} \right)}^{-\tfrac{1}{2}}}={{\left[ {{\left( \frac{2}{3} \right)}^{4}} \right]}^{\tfrac{1}{4}}}\times {{\left[ {{\left( \frac{4}{3} \right)}^{2}} \right]}^{-\tfrac{1}{2}}}=\frac{2}{3}\times \frac{3}{4}=\frac{1}{2} \\\end{align}$ 

Jamb Maths Topic: 
Year of Exam: