Question 7

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waecmaths question: 

If 2x = y, find ${{2}^{(2+\tfrac{x}{3})}}$

Option A: 

$4{{y}^{\tfrac{1}{3}}}$

Option B: 

$4{{y}^{-3}}$

Option C: 

$2{{y}^{\tfrac{1}{3}}}$

Option D: 

$2{{y}^{-3}}$

waecmaths solution: 

${{2}^{(2+\tfrac{x}{3})}}={{2}^{2}}\times {{2}^{\tfrac{x}{3}}}=4({{2}^{x}}\times {{2}^{\tfrac{1}{3}}})=4(y\times \tfrac{1}{8})=\tfrac{y}{2}$

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