Question 7

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waecmaths question: 

Simplify $\frac{3{{x}^{3}}}{{{(3x)}^{3}}}$

Option A: 

1

Option B: 

$\tfrac{1}{3}$

Option C: 

$\tfrac{1}{9}$

Option D: 

$\tfrac{1}{27}$

waecmaths solution: 

$\frac{3{{x}^{3}}}{{{(3x)}^{3}}}=\frac{3{{x}^{3}}}{27{{x}^{3}}}=\frac{1}{9}$

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