Question 8

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Jambmaths question: 

If${{\log }_{10}}2=x,$express ${{\log }_{10}}12.5$in terms of x

Option A: 

$2+3x$

Option B: 

$2-3x$

Option C: 

$2(1+x)$ 

Option D: 

$2(1-x)$

Jamb Maths Solution: 

$\begin{align}  & {{\log }_{10}}12.5={{\log }_{10}}\frac{100}{8} \\ & ={{\log }_{10}}100-{{\log }_{10}}8 \\ & ={{\log }_{10}}{{10}^{2}}-{{\log }_{10}}{{2}^{3}} \\ & =2{{\log }_{10}}10-3{{\log }_{10}}2 \\ & =2-3x \end{align}$

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