Question 8

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waecmaths question: 

One of the factors of $(mn-nq-{{n}^{2}}+mq)$ is (m – n). The other factor is

Option A: 

(mq)

Option B: 

(qn)

Option C: 

(n  + q)

Option D: 

(q m)

waecmaths solution: 

$\begin{align}  & mn-nq-{{n}^{2}}+mq=mn-{{n}^{2}}+mq-nq \\ & =n(m-n)+q(m-n) \\ & =(n+q)(m-n) \end{align}$The other factor (n + q)

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