Question 8

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Jambmaths question: 

Simplify $\frac{2\sqrt{2}-\sqrt{3}}{\sqrt{2}+\sqrt{3}}$

Option A: 

$3\sqrt{6}+7$

Option B: 

$3\sqrt{6}-1$

Option C: 

$3\sqrt{6}+1$

Option D: 

$3\sqrt{6}-7$

Jamb Maths Solution: 

$\begin{align}  & \frac{2\sqrt{2}-\sqrt{3}}{\sqrt{2}+\sqrt{3}}=\frac{2\sqrt{2}-\sqrt{3}}{\sqrt{2}+\sqrt{3}}\times \frac{\sqrt{2}-\sqrt{3}}{\sqrt{2}-\sqrt{3}} \\ & \frac{2\sqrt{2}-\sqrt{3}}{\sqrt{2}+\sqrt{3}}=\frac{8-\sqrt{6}-2\sqrt{6}+3}{2-3} \\ & \frac{2\sqrt{2}-\sqrt{3}}{\sqrt{2}+\sqrt{3}}=\frac{5-3\sqrt{6}}{-1}=3\sqrt{6}-5 \\\end{align}$

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