Question 9

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waecmaths question: 

Simplify $\frac{{{x}^{2}}-{{y}^{2}}}{{{(x+y)}^{2}}}\div \frac{{{(x-y)}^{2}}}{(3x+3y)}$

Option A: 

$\frac{x-y}{2}$

Option B: 

x + y

Option C: 

$\frac{3}{x-y}$

Option D: 

xy

waecmaths solution: 

$\begin{align}  & \frac{{{x}^{2}}-{{y}^{2}}}{{{(x+y)}^{2}}}\div \frac{{{(x-y)}^{2}}}{(3x+3y)}=\frac{(x-y)(x+y)}{{{(x+y)}^{2}}}\times \frac{3(x+y)}{{{(x-y)}^{2}}} \\ & =\frac{3}{(x-y)} \end{align}$

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