Question 9

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waecmaths question: 

Simplify $\frac{54{{k}^{2}}-6}{3k+1}$

Option A: 

$6(1-3{{k}^{2}})$

Option B: 

$6(3{{k}^{2}}-1)$

Option C: 

$6(3k-1)$

Option D: 

$6(1-3k)$

waecmaths solution: 

$\begin{align}  & \frac{54{{k}^{2}}-6}{3k+1}=\frac{6(9{{k}^{2}}-1)}{(3k+1)} \\ & =\frac{6(3k-1)(3k+1)}{(3k+1)} \\ & =6(3k-1) \end{align}$

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