Question 9

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waecmaths question: 

Find the equation whose roots are ¾ and –4

Option A: 

$4{{x}^{2}}-13x+12=0$

Option B: 

$4{{x}^{2}}-13x-12=0$

Option C: 

$4{{x}^{2}}+13x+12=0$

Option D: 

$4{{x}^{2}}+13x+12=0$

waecmaths solution: 

$\begin{align}  & (x-\tfrac{3}{4})(x+4)=0 \\ & {{x}^{2}}+4x-\tfrac{3}{4}x-3=0 \\ & 4{{x}^{2}}+16x-3x-12=0 \\ & 4{{x}^{2}}+13x-12=0 \\\end{align}$

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